In the article Data
Structures: Introduction to Stacks, we saw that there was one major
disadvantage of representing stacks using arrays- the stack like the array could
have a limited number of elements, while stacks should be able to grow up to
any number of elements. Besides this there were other disadvantages too.
In one of the other article about Linked
Lists, we noticed one useful property of linked lists that they can
grow up to any size to accommodate for the addition of elements and it efficiently
uses the memory too.
So if we combine both of this to from a linked version of the stack then it
won’t have the shortcomings that the array version had.
This is what this article is all about.
pushing and popping
As you know that addition of elements to the stack is known as pushing while
retrieval is known as popping.
The process of pushing and popping in case of linked version of stack is slightly
different from the array version. The following graphics will clear it though!
FIG: pushing of elements in the linked stack
FIG: popping of the elements from the linked
stack
Now that you know how the basic operations are performed on linked stacks I
present you with the example program to illustrate this.
As always I would strongly recommend you to read the comments!
// -- Linked stacks --
// Example program to
// illustrate basic
// push and pop to a
// linked stack
#include<iostream.h>
// node class, this will
// represent the nodes or elements
// of the linked stacks
class node
{
public:
int info;
node *link;
};
// declare global objects
node *start=NULL;
// function prototypes
void push(int);
int pop();
void main(void)
{
int ch=0,num;
while(ch!=3)
{
cout<<"1> Push";
cout<<"\n2> Pop";
cout<<"\n3> Quit\n";
cin>>ch;
switch(ch)
{
case 1:
cout<<"enter element:";
cin>>num;
push(num);
break;
case 2:
cout<<"\n\nPopped: ";
cout<<pop();
cout<<"\n\n";
break;
}
}
// below is a bit confusing
// part.
// here all the nodes that
// we have allocated are
// being freed up
node temp;
while(start!=NULL)
{
// store the next node
// to the one being deleted
temp=*start;
// delete the node
delete start;
// retrieve the next node
// to be deleted
start=temp.link;
}
}
// pushes an element 'inf'
// to the linked stack
void push(int inf)
{
node *temp1;
node temp2;
// if the element to be added
// is the first element of
// linked stack
if(start==NULL)
{
// allocate a new node
temp1=new node;
temp1->info=inf;
temp1->link=NULL;
// make start point at it
start=temp1;
}
// if not
else
{
// store the information
// about the node pointed
// by 'start'
temp2.info=start->info;
temp2.link=start;
temp1=new node;
temp1->info=inf;
// insert the new node
// at the beginning
// and make its link
// point to the prev.
// node pointed by 'start'
temp1->link=temp2.link;
start=temp1;
}
}
// returns an element from the
// linked stack
int pop()
{
node temp;
if(start!=NULL)
{
// store info. about
// the first element
// that has to be pooped
temp=*start;
// delete the node
delete start;
// make start point at the
// next node which had been
// stored
start=temp.link;
return temp.info;
}
return NULL;
}
Good-Bye!
Related Articles: